lop P = log Po - clog(t+1)
log P = log Po - log(t+1)^c Move coefficient to exponent.
log P = log Po/((t+1)^c) Subtract logs = divide.
P = Po/((t+1)^c) If 2 logs are equal then the thing you take log of are equal.
I think this is how it works.
I'll give anyone a rep if they can answer this for me + explain each step.
log P = log P0 - c log(t+1)
solve for P
Thanks ;-;
lop P = log Po - clog(t+1)
log P = log Po - log(t+1)^c Move coefficient to exponent.
log P = log Po/((t+1)^c) Subtract logs = divide.
P = Po/((t+1)^c) If 2 logs are equal then the thing you take log of are equal.
I think this is how it works.
whatareyoudoingomgSTOP(02-05-2012)
omg you're so smart are you a math teacher?
thank you! ;-; this was the only one i was stuck with and now...I COMPLETEH THE HOMEWORKEH.
nevermind
Last edited by whatareyoudoingomgSTOP; 02-05-2012 at 09:58 PM. Reason: answered my own question