screw it I am dumb
Pls help with my homework
This is the question I'm doing. Will +rep for an explanation on how to do it properly.
The answer is 18.
The polynomial equation x^3 - ax^2 + bx - c = 0, where a, b, and c are integers, and it has 6 as on of its roots. According to the rational root theorem, what is the value of c?
Last edited by Aura; 12-16-2016 at 12:49 AM.
i love luna
screw it I am dumb
Last edited by Stocking Anarchy; 12-16-2016 at 12:14 AM.
Aura (12-16-2016)
You sure the original Q is not
x^3 - ax^2 + bx - c = 0 ?
Are we 100% sure the value of C is 18? @(you need an account to see links)
Last edited by Byte; 12-16-2016 at 09:02 AM.
(x−1)(x−1)(x−6) = x^3−8x^2+13x−6
That's why I was asking. I'll do some more thinking on it, it's confusing to me how to figure out the coefficients of the equation, and to use the rational root theorem, and use synthetic division without them. I feel like a piece of the question is missing.
Aura (12-16-2016)
I asked my teacher and this is his explanation:
Using the rational root theorem, c/1 has to equal 6 somehow. He said that 18 was the only answer that was even a factor of 6 (the other choices were 2, 3, and 9; I didn't think I had to include them in this thread though lol. That probably would've helped.)
That was way easier than I thought. thanks for all of your help, though, guys.
i love luna