1. Pre-calc help pls

Pls help with my homework
This is the question I'm doing. Will +rep for an explanation on how to do it properly.

The polynomial equation x^3 - ax^2 + bx - c = 0, where a, b, and c are integers, and it has 6 as on of its roots. According to the rational root theorem, what is the value of c?

2. screw it I am dumb

3. The Following User Says Thank You to Stocking Anarchy For This Useful Post:

Aura (12-16-2016)

4. Originally Posted by Stocking Anarchy
screw it I am dumb
thanks for trying though you da MVP

still need help

5. You sure the original Q is not

x^3 - ax^2 + bx - c = 0 ?

6. Originally Posted by Stocking Anarchy
You sure the original Q is not

x^3 - ax^2 + bx - c = 0 ?
Oops, yes, it was supposed to be, haha, thank youu

Maybe it'll be easier to help now?!

7. Are we 100% sure the value of C is 18? @(you need an account to see links)

8. Originally Posted by Revelation343
Are we 100% sure the value of C is 18? @(you need an account to see links)
Yeah, 100%. I have the answers, just not the process.

9. Originally Posted by Aura
Yeah, 100%. I have the answers, just not the process.
(x−1)(x−1)(x−6) = x^3−8x^2+13x−6

That's why I was asking. I'll do some more thinking on it, it's confusing to me how to figure out the coefficients of the equation, and to use the rational root theorem, and use synthetic division without them. I feel like a piece of the question is missing.

10. The Following User Says Thank You to Byte For This Useful Post:

Aura (12-16-2016)

11. Originally Posted by Revelation343
(x−1)(x−1)(x−6) = x^3−8x^2+13x−6

That's why I was asking. I'll do some more thinking on it, it's confusing to me how to figure out the coefficients of the equation, and to use the rational root theorem, and use synthetic division without them. I feel like a piece of the question is missing.
I asked my teacher and this is his explanation:
Using the rational root theorem, c/1 has to equal 6 somehow. He said that 18 was the only answer that was even a factor of 6 (the other choices were 2, 3, and 9; I didn't think I had to include them in this thread though lol. That probably would've helped.)
That was way easier than I thought. thanks for all of your help, though, guys.

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