Solving for y (+rep)

[learningtoneopet1]

Solved

[boomer]

Recognize that 2y-6 is just 2(y-3).

Rewrite the equation with common denominator so it looks like
6/2(y-3) = -1/2(y-3) + 2(y-3)/2(y-3)

Now multiply 2(y-3) from the left side to the right, so now the denominators cancel out.

You are left with:
6 = -1 + 2(y-3)
6 = -1 + 2y - 6
13 = 2y
y= 13/2 or 6.5

[tzh440]

[3/(y-3)] = [(-1+2y-6)/(2y-6)]
[3/(y-3)] = [(2y-7)/(2y-6)]
cross multiplying,
[3(2y-6)] = [(y-3)(2y-7)]
[6y-18] = [(2y^2)-7y-6y+21]
[6y-18] = [(2y^2)-13y+21]
0=(2y^2)-13y+21-6y+18
0=(2y^2)-19y+39
0=(y-3)(2y-13)
thus, y=3( reject), y=13/2

tell me if you do not understand my working

[learningtoneopet1]

Thank guys!

You must spread some Reputation around before giving it to boomer again.

I'll rep you when I can @(you need an account to see links)