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John
01-31-2012, 11:01 AM
1. Translate the statement below to an equation using absolute value and solve:
The distance between 50 and me is at least 10.


2. Using the given zero, find all of the zeros and write a linear factorization of f(x).

1+3i is a zero of f(x)=x^4-2x^3+5x^2+10x-50

Carrot
01-31-2012, 03:19 PM
1. Translate the statement below to an equation using absolute value and solve:
The distance between 50 and me is at least 10.

|x-50| ≥ 10

John
01-31-2012, 03:21 PM
thanks homie

Carrot
01-31-2012, 03:32 PM
No problem. I don't remember how to do #2 though D:

---------- Post added at 03:32 PM ---------- Previous post was at 03:23 PM ----------

[Only registered and activated users can see links] 4-2x%5E3%2B5x%5E2%2B10x-50

bamag
01-31-2012, 03:43 PM
1+3i is a zero of f(x)=x^4-2x^3+5x^2+10x-50
Since 1+3i is a root, 1-3i is also a root. ((x-1)-3i)((x-1)+3i)=(x-1)^2-(3i)^2=x^2-2x+1-9i^2=x^2-2x+10
Use long division to get x^2-5.
Find the two roots of that are +- radical 5.
Therefore, all the zeroes are 1+3i,1-3i, radical 5, negative radical 5.
Linear factorization is f(x)=(x-1-3i)(x-1+3i)(x+5^.5)(x-5^.5)

dodowong303
02-01-2012, 03:59 AM
1+3i is a zero of f(x)=x^4-2x^3+5x^2+10x-50
Since 1+3i is a root, 1-3i is also a root. ((x-1)-3i)((x-1)+3i)=(x-1)^2-(3i)^2=x^2-2x+1-9i^2=x^2-2x+10
Use long division to get x^2-5.
Find the two roots of that are +- radical 5.
Therefore, all the zeroes are 1+3i,1-3i, radical 5, negative radical 5.
Linear factorization is f(x)=(x-1-3i)(x-1+3i)(x+5^.5)(x-5^.5)



it is cool, but you may give the explanation that why 1-3i is also a root.


you may add [since all coefficient are real number, therefore (a+bi)(1+3i)=constant +0i,hence a=1,b=3 ]

bamag
02-01-2012, 03:08 PM
it is cool, but you may give the explanation that why 1-3i is also a root.


you may add [since all coefficient are real number, therefore (a+bi)(1+3i)=constant +0i,hence a=1,b=3 ]

It is simply the conjugate roots theorem. If a+bi is a root, then a-bi is also a root, and vise versa.

dodowong303
02-01-2012, 11:59 PM
It is simply the conjugate roots theorem. If a+bi is a root, then a-bi is also a root, and vise versa.

i know but my teacher will deduct marks form missing some stupid simple explanation such as a+bi&a-bi must be pair,etc.......==