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Ray-Chill
01-16-2012, 11:28 PM
Anyone know how to do this?
I can't see to get the answer right..
[Only registered and activated users can see links]{{\frac{{{{x}}^{{2}}%2B{3}{x}-{4}}}{{{{x}}^{{2}}-{7}{x}%2B{12}}}}}{{\frac{{{x}%2B{4}}}{{{x}-{3}}}}}

zlolekim
01-16-2012, 11:49 PM
Hmm i cant see whats goin on

Ray-Chill
01-16-2012, 11:50 PM
It's all dividing by it's self..
Can you not see the picture? lol

zlolekim
01-16-2012, 11:52 PM
do you have the link to the picture because its tiny

Ray-Chill
01-16-2012, 11:54 PM
[Only registered and activated users can see links] D%5E%7B%7B2%7D%7D%2B%7B3%7D%7Bx%7D-%7B4%7D%7D%7D%7B%7B%7B%7Bx%7D%7D%5E%7B%7B2%7D%7D-%7B7%7D%7Bx%7D%2B%7B12%7D%7D%7D%7D%7D%7B%7B%5Cfrac %7B%7B%7Bx%7D%2B%7B4%7D%7D%7D%7B%7B%7Bx%7D-%7B3%7D%7D%7D%7D%7D

doubt you'll be able to see it as it's on my homework. lol

zlolekim
01-17-2012, 12:00 AM
(x-1)
----- <division sign
(x-4)

Ray-Chill
01-17-2012, 12:07 AM
I understand that.. i dont' understand how to do the whole entire problem..

zlolekim
01-17-2012, 12:11 AM
Umm okay

reverse foil the top two lines
x^2+3x-4 become (x+4)(x-1)
x^2-7x+12 becomes (x-3)(x-4)

(x+4)(x-1)
----------
(x-3)(x-4)
-------------
x+4
--------------
x-3

now cross out the x-3 and x+4
and you are left with
(x-1)
----- <division sign
(x-4

Khelddar
01-17-2012, 01:36 AM
Umm okay

reverse foil the top two lines
x^2+3x-4 become (x+4)(x-1)
x^2-7x+12 becomes (x-3)(x-4)

(x+4)(x-1)
----------
(x-3)(x-4)
-------------
x+4
--------------
x-3

now cross out the x-3 and x+4
and you are left with
(x-1)
----- <division sign
(x-4

Looks like you don't need my help.

zlolekmin answer is correct.

BlackSheep
01-17-2012, 03:50 AM
Jesus lord :P .. Maybe I should hold on to my gun for a few more years :P Going back to college just got a lot less appealing to me :P