Requesting More Math Help [I really should just make my own board Ed.]

[Maki]

So I've got EQAO tomorrow (yay) ((not))

Been going through the practice booklet~

Alfredo and his wife, Jody, work in a
restaurant.
Last week Alfredo received an average of
$15 in tips for each of the 55 tables he
served. Jody received an average of $20 in
tips for each of the 60 tables she served.
They are planning a weekend trip. Alfredo
will pay a total of $220 for their hotel room
and Jody will pay a total of $160 for their
rental car.
How much of their combined tips will be
left over after they have paid for their hotel
room and rental car?

a $1620
b $1645
c $2025
d $2405

Help? D:

[Flame]

(55*15)+(60*20)-380 = 1645
==because $15 average for each 55 table he served==
==$20 average for each 60 tables===
== minus 380(which is total they spent= 1645 left over

B.

[Maki]

Oh okay, thanks babytroop123456 !

I have another:

Juan belongs to a CD club that sells CDs for $11.44 each before tax. His first shipment of CDs costs
$90.49 including 13% tax.
How many CDs are in his first shipment?

I got 7.

[Flame]

Can you explain what you did? I don't really understand the question :c

edited my post, so theres an explanation

[Maki]

Edited my post as well xD

[Graff]

90.49= 11.44(x)+(.13)(11)(x)

you can do the algebra

[Flame]

Oh okay, thanks babytroop123456 !

I have another:

Juan belongs to a CD club that sells CDs for $11.44 each before tax. His first shipment of CDs costs
$90.49 including 13% tax.
How many CDs are in his first shipment?

I got 7.

11.44x + .13(11.44x) = 90.49
its 7. So you're right. THe equation is above^

[Maki]

Here's what I have on my paper.

$11.44- before tax, each CD.

90.49(0.13)
= $11.76 <-- tax

90.49-11.76
= $78.73

$78.73/$11.44
= around 7 CDs

[Flame]

Here's what I have on my paper.

$11.44- before tax, each CD.

90.49(0.13)
= $11.76 <-- tax

90.49-11.76
= $78.73

$78.73/$11.44
= around 7 CDs

That also works, but solving it alagabbraeicly would result in the equations me and graff posted

[Maki]

Alright, understood! Thanks Graff babytroop123456 ~

Here's another one:

A box with a volume of 12x^y^2 is
shown below. (height 2y & length 2x)

What is the width of the box?

[Flame]

Alright, understood! Thanks Graff babytroop123456 ~

Here's another one:

A box with a volume of 12x^y^2 is
shown below. (height 2y & length 2x)

What is the width of the box?

im asuming you ment "*" not "^"
which in that case would mean the answer is 6

12xy(2)=24xy
2y(2x)=4xy
4xy * 6 = 24xy

width = 6

[Maki]

Oops, I meant 12x^2(y^2)

to the power of*

[Flame]

Oops, I meant 12x^2(y^2)

to the power of*

so 12x to the power of 2y squared?(2y^2)

[Maki]

12(x^2)(y^2) :P babytroop123456

[Flame]

12(x^2)(y^2) :P babytroop123456

its 3xy. im positive. what does it want it entered as?

[Maki]

i personally got 4xy, but what does it want it as?

The options say:

a 2xy
b 3xy
c 4(x^3)(y^3)
d 8(x^3)(y^3)

The correct one is b

[Flame]

The options say:

a 2xy
b 3xy
c 4(x^3)(y^3)
d 8(x^3)(y^3)

The correct one is b

lol ya. i got 4 because i accidently divide 12/4 wrong. you solve as follows:
[Only registered and activated users can see links]

[Maki]

Ahhhhh, I sort of get it.
Thanks!
You must spread some Reputation around before giving it to babytroop123456 again. D:
Totally will the next time I am able, though~

---------- Post added at 05:54 PM ---------- Previous post was at 05:23 PM ----------


lol ya. i got 4 because i accidently divide 12/4 wrong. you solve as follows:
[Only registered and activated users can see links]

Wait, why 4xyz?

[Flame]

Ahhhhh, I sort of get it.
Thanks!
You must spread some Reputation around before giving it to babytroop123456 again. D:
Totally will the next time I am able, though~

---------- Post added at 05:54 PM ---------- Previous post was at 05:23 PM ----------



Wait, why 4xyz?

Length*Height = 4xy
We let z stand for the unknown, which in this case is width(you could also do "w" as the unkown. Doesnt matter which).

[Frank12]

He's just simplifying the equation. When you set it up you can remove a 4xy from both sides, isolating the z (width). He was stating that he divided the 12/4 incorrectly and got 4xy, when he meant to have 3xy

The correct answer is, as stated in his picture, 3xy

[tchaikovsky]

Mint

In the first step illustrated by babytroop (don't know your name haha) the 4 and the twelve are cancelled out to leave just 3 on the right side of the equation. The 4 is what you're dividing the whole thing by to leave you with xyz=3x^2y^2.

[Frank12]

You stated the volume was 12(x^2)(y^2)

V = (length)(height)(Width)

solve for width

12(x^2)(y^2)= (2x)(2y)(width)

12(x^2)(y^2) = 4xy(width)

Divide everything by 4

3(x)(x)(y)(y) = xy(width) *broke apart the squares for easier understanding

Remove an x and y from both sides

3(x)(y) = width

[Maki]

You stated the volume was 12(x^2)(y^2)

V = (length)(height)(Width)

solve for width

12(x^2)(y^2)= (2x)(2y)(width)

12(x^2)(y^2) = 4xy(width)

Divide everything by 4

3(x)(x)(y)(y) = xy(width) *broke apart the squares for easier understanding

Remove an x and y from both sides

3(x)(y) = width

Love this explanation, thanks so so so so so so much!

+ repped to Graff, Frank, and tchaikovsky :p

I have another question!

A high school is starting a recycling program.
The relationship between the total cost of the program, C, and the number of recycling bins, n, is
represented by the equation C = 48n + 75.
The school must install a minimum of 12 recycling bins and has a maximum of $1000 to spend on
the program.
What are the possible values of C and n in this situation?

[Frank12]

Love this explanation, thanks so so so so so so much!

+ repped to Graff, Frank, and tchaikovsky :p

I have another question!

A high school is starting a recycling program.
The relationship between the total cost of the program, C, and the number of recycling bins, n, is
represented by the equation C = 48n + 75.
The school must install a minimum of 12 recycling bins and has a maximum of $1000 to spend on
the program.
What are the possible values of C and n in this situation?

TY.

C = 1000> or =

n = 12< or =

C = 48(n) + 75

C - 75 = 48n

C = 925 > or =

Divide both sides by 48

925 / 48 = 19.2708 ~ 19

All possible values for n = 12 through 19.

Put 12, 13, 14, 15, 16, 17, 18, 19 into the equation and solve for C.

Lowest will be 576, highest will be 987

If you need all the answers, I can do the math out.

[Maki]

TY.

C = 1000> or =

n = 12< or =

C = 48(n) + 75

C - 75 = 48n

C = 925 > or =

Divide both sides by 48

925 / 48 = 19.2708 ~ 19

All possible values for n = 12 through 19.

Put 12, 13, 14, 15, 16, 17, 18, 19 into the equation and solve for C.

Lowest will be 576, highest will be 987

If you need all the answers, I can do the math out.

Thanks! Can you give me 19-15?

[Frank12]

Thanks! Can you give me 19-15?

when n = 12 is 651
when n = 13 is 699
when n = 14 is 747
when n = 15 is 795
when n = 16 is 843
when n = 17 is 891
when n = 18 is 939
when n = 19 is 987

I apologize for the 576 in my original post, I forgot to add the 75 xD

[Maki]

Frank12 Oh, thank you again!

I've been through 2 EQAO practice booklets, and I'm a little nervous haha I'm so sorry for bombarding you with questions.

I think I'm all set----- for today, LOL

Thanks very much xo