Math Question - I'm a bit rusty on this.

[Bettser]

So its just simplifying things;

2(a-1)(7a-3) - 3(6a-2)(2a+1)

I'm just trying to remember if;

2(a-1)(7a-3)

The 2 applies to both brackets or just the first one. Thanks

[pudgyboy]

Yes the 2 applies to both brackets


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---------- Post added at 12:25 PM ---------- Previous post was at 12:24 PM ----------

Err parenthesis*. Brackets are actually different in math


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[Bettser]

Yes the 2 applies to both brackets


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---------- Post added at 12:25 PM ---------- Previous post was at 12:24 PM ----------

Err parenthesis*. Brackets are actually different in math


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So would that side be;

(2a-2)(14a-6)

or 2(7a^2 -3a - 7a +4)

[pudgyboy]

Hold on, I believe it only applies to the first one LOL. Let me check my math real quixk


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[Bettser]

Hold on, I believe it only applies to the first one LOL. Let me check my math real quixk


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From what I remember, it only applies to the first. Not sure though which is why I'm asking xD

[Lmp]

Applies to one.
You can multiply the 2 with the first parenthesis, than multiple both parenthesis, or multiply the parenthesis out first, than multiply the 2 to it.

Example:

2(x+3)(x+3) where x = 0
2(3)(3) = 18

[Charlie]

It's both, for the first set of parentheses.
Think: 2(FOIL METHOD). So do the foil method, then multiple it by 2.

Hmm, honestly multiplication should be able to be applied at any moment. That's what's so great about it.

[Aura]

It applies to the first one only, I'm pretty sure.

[pudgyboy]

Yeah it's only the first one the 2 applies to.
So if you applied the 2 you'd get:
(2a-2)(7a-3)
=> (14a^2 - 14a - 6a +6)
==> (14a^2 -20a +6)
===> 2(7a^2 - 10a + 3)
Which is the same as if you foiled first:
2(a-1)(7a-3)
=> 2(7a^2 - 7a - 3a +3)
==> 2(7a^2 - 10a + 3)


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[Charlie]

Here's the solution to the first half:

FOIL = First, Outside, Inside, Last

2(a-1)(7a-3)
=2 (7a^2 - 3a - 7a + 3)
=2 (7a^2 - 10a + 3)
=14a^2 - 20a + 6

This thread makes me miss math