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Thread: Math help. +rep

  1. #1
    Ray-Chill's Avatar
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    Math help. +rep

    Ah!! Help!!

    I'm so freaking lost...

    I have (1+cos(y))/(1+sec(y))

    I need to simplify it in terms of cos/sin..

    I'm stuck.. I don't understand how to get the fraction off..
    Last edited by Ray-Chill; 04-16-2012 at 09:26 PM. Reason: New problem..
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    bamag's Avatar
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    y=3*4^x
    y=12*5^x
    For 1st one, you see the 3 so you factor that out, and from there its pretty obvious.
    For 2nd, since when x is 0, y is 12, that means a = 12. Then from there you can figure out the rest pretty easily.
    Last edited by bamag; 03-12-2012 at 08:47 PM.

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    Ana's Avatar
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    An exponential function f(x)=a⋅bx passes through the points (0, 12) and (3, 1500). What are the values of a and b?

    start with using (0, 12)
    12=a*b^0
    12=a

    then plug in the second point
    (3, 1500)
    1500=12*b^3
    125=b^3
    5=b

    a= 12
    b=5

    ---------- Post added at 08:55 PM ---------- Previous post was at 08:47 PM ----------

    Do you want the work for number 1?

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    Ray-Chill (03-12-2012)

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    Ray-Chill's Avatar
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    =] No thanks. Lol My homework is all online so she can't see it anyways. =]
    Might have somemore problems later.
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    �Of course it hurts, it�s a spanking. How else would it work?�


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    Ray-Chill's Avatar
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    8^(8x-3)=5^(10x-6)
    Solve for x..
    Please =]
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  7. #6
    bamag's Avatar
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    My bad :p
    Last edited by bamag; 03-13-2012 at 11:49 PM.

  8. #7
    Zachafer's Avatar
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    There are definitely real solutions...

    Exact answer is x=(9log(2)-6log(5))/(24log(2)-10log(5))

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    Ray-Chill (03-14-2012)

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    8^8x-3 = 5^10x-6
    (8x-3) * log8 = (10x-6) * log5
    (8x-3) * 0.903 = (10x-6) log5
    7.242x - 2.709 = 6.99x - 4.194
    0.234x = -1.485
    x = -6.346

    @(you need an account to see links), almost the same amswer as Zachafer

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    Ray-Chill (03-14-2012)

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    Ray-Chill's Avatar
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    I love you guys.. You have no idea!

    Saved my life.
    ~ <3 ~ <3 ~ <3 ~ <3 ~


    �Of course it hurts, it�s a spanking. How else would it work?�


  13. #10

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    Quote Originally Posted by Ray-Chill View Post
    I love you guys.. You have no idea!

    Saved my life.
    No problem. If you need any help in math (or other subjects) around the same level of difficulty you can pm me!

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    Ray-Chill (03-14-2012)

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