y=3*4^x
y=12*5^x
For 1st one, you see the 3 so you factor that out, and from there its pretty obvious.
For 2nd, since when x is 0, y is 12, that means a = 12. Then from there you can figure out the rest pretty easily.
Ah!! Help!!
I'm so freaking lost...
I have (1+cos(y))/(1+sec(y))
I need to simplify it in terms of cos/sin..
I'm stuck.. I don't understand how to get the fraction off..
Last edited by Ray-Chill; 04-16-2012 at 09:26 PM. Reason: New problem..
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�Of course it hurts, it�s a spanking. How else would it work?�
y=3*4^x
y=12*5^x
For 1st one, you see the 3 so you factor that out, and from there its pretty obvious.
For 2nd, since when x is 0, y is 12, that means a = 12. Then from there you can figure out the rest pretty easily.
Last edited by bamag; 03-12-2012 at 08:47 PM.
An exponential function f(x)=a⋅bx passes through the points (0, 12) and (3, 1500). What are the values of a and b?
start with using (0, 12)
12=a*b^0
12=a
then plug in the second point
(3, 1500)
1500=12*b^3
125=b^3
5=b
a= 12
b=5
---------- Post added at 08:55 PM ---------- Previous post was at 08:47 PM ----------
Do you want the work for number 1?
Ray-Chill (03-12-2012)
=] No thanks. Lol My homework is all online so she can't see it anyways. =]
Might have somemore problems later.
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�Of course it hurts, it�s a spanking. How else would it work?�
8^(8x-3)=5^(10x-6)
Solve for x..
Please =]
~ <3 ~ <3 ~ <3 ~ <3 ~
�Of course it hurts, it�s a spanking. How else would it work?�
My bad :p
Last edited by bamag; 03-13-2012 at 11:49 PM.
There are definitely real solutions...
Exact answer is x=(9log(2)-6log(5))/(24log(2)-10log(5))
Ray-Chill (03-14-2012)
8^8x-3 = 5^10x-6
(8x-3) * log8 = (10x-6) * log5
(8x-3) * 0.903 = (10x-6) log5
7.242x - 2.709 = 6.99x - 4.194
0.234x = -1.485
x = -6.346
@(you need an account to see links), almost the same amswer as Zachafer
Ray-Chill (03-14-2012)
I love you guys.. You have no idea!
Saved my life.
~ <3 ~ <3 ~ <3 ~ <3 ~
�Of course it hurts, it�s a spanking. How else would it work?�
Ray-Chill (03-14-2012)