Oh I was too lazy to write the last step. You merge x^5 with the other term and then it becomes (x(y/x+3))^5. You can merge them because they are both ^5
Oooh, Jeez. I get it now! The extra x was applied to the x^4 to get x^5, that is multiplied in to get just y and 3x. Jeeeez I was stuck on that for so long. Haha, Thank you much!