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Thread: Free calculus help from engineer

  1. #11


    kat.'s Avatar
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    Quote Originally Posted by Yumemi View Post
    Oh I was too lazy to write the last step. You merge x^5 with the other term and then it becomes (x(y/x+3))^5. You can merge them because they are both ^5
    Oooh, Jeez. I get it now! The extra x was applied to the x^4 to get x^5, that is multiplied in to get just y and 3x. Jeeeez I was stuck on that for so long. Haha, Thank you much!

    +rep

  2. The Following User Says Thank You to kat. For This Useful Post:

    Yumemi (05-27-2017)

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