Uhhh basically, I just used normal trigonometry LOL. Your method works too, though, and that's probably the way they were asking her to do it. But it seemed easier this way.
Basically I drew up 2 triangles, whereby the
First one (JBLM to undisclosed area), where tanx = 154/239, therefore x=34.45762
Second one (JBLM to Mt. Rainier), where tany= 40/56, therefore y=35.53767779
- Also, on the second triangle, you find the other length (a^2+b^2=c^2, where c= 68.81860215)
Uhm, if you drew it out according to the question, then the angle in between the two triangles is simply 90-x-y=20 degrees.
Since you want the perpendicular distance from Mt. Rainer, you simply say that cos(z)=LENGTH/68.81860215
(Where LENGTH is the distance travelled by the plane).
So LENGTH = 68.81860215 x cos(z)
Therefore LENGTH = 64.6683326
And for every 800km, divide the LENGTH by 800, which is 0.08.
I hope I explained that simply LOL. If you draw it out you'll get it without my explanation. :p
Oh trig lol. Can't believe I forgot all about it considering I took it last year lol :p
Anyways you're methods seems a lot less painful and that's probably how she's supposed to do it.
My solution is too ugly lol
Well she said to use the perpendicular/distance etc formula, so I'm supposing that the other questions needed it?
Don't worry, I've missed easy solutions before and I end up answering questions in many more lines that needed. :p
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