need someone to help do Algerba 2 Review sheets 2night! Thanks!

[5252]

need someone to help do Algerba 2 Review sheets 2night! Thanks!

[boomer]

@(you need an account to see links) PM me I'll give it a go

[5252]

thanks, but lazy/busy:.....

Write in factored form: y=ax (3rd power) + b X(squared) + cX + d -----------> (x-r1)(x-r2)(x-r3)

y= x(3rd power) + 2 x squared - 19x - 20


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#2

evaluate: (2+3i) (4-5i)

__________

#3

add

x 9
- + -
(x-5) (x+1)

multiply

(x+3) (x+5)(x-3)
------ x ----------
(x-3) (x+3)

[boomer]

@(you need an account to see links)

y = x^3 + 2x^2 - 19x - 20
y = (x - 4)(x + 1)(x + 5)
My method: guess and check D:
You know the term without x has to be 20 so your numbers have to be factors that multiply to 20, and you go from there.

(2+3i) (4-5i)
= 8 - 10i + 12i - 15i^2
= 23 + 2i
Because i^2 = -1

Assuming you meant
x / (x-5) + 9 / (x+1)
= (x^2 + 10x - 45) / (x-5)(x+1)
Find common denominator, change both fractions to have common denominator, then add.

(x+3) (x+5)(x-3)
------ x ----------
(x-3) (x+3)

x+3 and x-3 both cancel out (present in both top and bottom of the fraction)
Answer is x+5

[Water]

@(you need an account to see links)
P(-1) = (-1)^3 + 2(-1)^2 - 19(-1) - 20
= -1 + 2 - 19 - 20
= 0
x+1
x^2 + x - 20
x+1 / x^3 + 2x^2 - 19 x - 20
x^3 + x^2
x^2 - 19x
x^2 + x
- 20x - 20
20x - 20
0
(x + 1)x^2 + x - 20
(x + 1)(x-4)(x+5)

PM if you need a picture of the working out ^__^